如题，使用 python 编写了个发送邮件的 Demo 。邮件发送后，用 Foxmail 能够正常收的到。
但是收件人一栏显示的收件邮箱很奇怪，如下图，一整个收件邮箱被按字符拆分为好多个小邮箱，小邮箱的那域名我也没见过。
原本收件邮箱应该显示是 [email protected]
不知道有大佬遇到过这种情况没，请教下

下面是源码（看着没毛病）： # 编译日期：2019-10-14 15:01:36 # coding=utf-8 import os from email.mime.text import MIMEText from email.header import Header from email.mime.multipart import MIMEMultipart from email.mime.application import MIMEApplication # 发送邮件（附件） # email_user: 发件人 # email_pass: 密码 # receivers：收件人列表，例：[' [email protected] ',' [email protected] '] # filepath: 文件地址 如：r'D:\分行查询支行卷别库存 Excel\作文.xlsx' def sendEmail(email_user, email_pass, receivers, filepath): mail_host = '10.10.10.10' # 设置服务器地址 sender = email_user + '@xxx.com.cn' # 发件人邮箱 # 创建一个带附件的实例 message = MIMEMultipart() # 设置发件人、收件人 message['From'] = sender message['To'] = ", ".join(receivers) # 设置邮件主题 message['Subject'] = Header('查冻扣报备文件', 'utf-8') # 邮件正文 message.attach(MIMEText('查冻扣报备文件已发送，请查看附件！', 'plain', 'utf-8')) # 构造附件 xlsx = MIMEApplication(open(filepath,'rb').read()) xlsx['Content-Type'] = 'application/octet-stream' filename = os.path.basename(filepath) xlsx.add_header('Content-Disposition', 'attachment', filename=Header(filename, 'utf-8').encode()) message.attach(xlsx) try: smtpObj = smtplib.SMTP(mail_host, 1025) smtpObj.login(email_user, email_pass) smtpObj.sendmail(sender, receivers, message.as_string()) print("邮件发送成功，收件人：" + str(receivers) + "\n 附件地址:" + str(filepath)) except smtplib.SMTPException as e: print("邮件发送失败，收件人：" + str(receivers) + "\n 附件地址:" + str(filepath)) print(e)